603, 606, ... (64 more of them).
242 = 576
5
7 is not divisible by any of them.
600 ÷ 17 = 355/17 2000 ÷ 17 = 11711/17 → 117 - 35 = 82 integers between 600 and 2000 are divisible by 17.
540/4=135 540/10=54
The number halfway between them is 600.
For a number to be divisible by 3, its digit sum has to be divisible by 3. For a number not to be divisible by 2, the last digit must be a 1,3,5,7 or 9. Using these rules, the numbers between 500 and 600 that divide by 3 but not 2 become clear: 501, 507, 513, 519, 525, 531, 537, 543, 549, 555, 561, 567, 573, 579, 585, 591 and 597
9
500
603, 606, ... (64 more of them).
The halfway point between 500 and 600 is (500 + 600) ÷ 2 = 550
The number is 536.
242 = 576
There are 22 numbers between 400 and 600 that are divisible by nine.
7
The first number is 501. Add three to that, and you get the next one. Keep going until you reach 600, and you'll find all the numbers divisible by three. I'm assuming this is part of an assignment given to you, and I'll explain how you can do it, but I'm not going to do the work for you.