There are infinitely many numbers divisible by 63, just multiply 63 by any whole number and you'll get one.
126 is divisible by 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126.
Yes they are. They are both divisible by 7. 14/2= 7 and 63/9=7
63 is a composite number because it is divisible by 3 and 21 in addition to 1 and itself.
315
To find the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63, we need to find the least common multiple (LCM) of these four numbers. The LCM of 42, 49, 56, and 63 is 1764. To make 3500 divisible by 1764, we need to find the remainder when 3500 is divided by 1764, which is 1972. Therefore, the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63 is 1764 - 1972 = 208.
Here are some of them: 21, 42, 63, 84, 105, 126, 147, 168.
63
A number that is divisible by both 3 and 7 must be a multiple of their least common multiple, which is 21. Therefore, any number that is a multiple of 21 will be divisible by both 3 and 7. Examples of such numbers include 21, 42, 63, 84, and so on.
There are infinitely many numbers divisible by 63, just multiply 63 by any whole number and you'll get one.
14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, & 98
The difference between a number and its reverse must be divisible by 9. 42 is NOT divisible by 9. There is, therefore, no such number.
33% To find out this out, subtract the larger number by the smaller number (63 - 42). Then divide the result (21) by the original number (63) and then you get the answer (21 divided by 63 = 0.333... = 33.333...%
Yes. The number 63 is divisible by 3 and by 7 and by 9. Since 3 x 3 x 7 = 63 as you can see, the number 63 is composite. A composite number is divisible by an integer (counting number) other than 1 and itself.
No, it is divisible by: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126
126 is divisible by 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126.
Yes they are. They are both divisible by 7. 14/2= 7 and 63/9=7