16 -9
-7 and -6 is one pair. 6 and 7 is the other, more boring pair.-7 and -6 is one pair. 6 and 7 is the other, more boring pair.-7 and -6 is one pair. 6 and 7 is the other, more boring pair.-7 and -6 is one pair. 6 and 7 is the other, more boring pair.
Yes.
They are 3 and 7
7 and 35
16 -9
Oh, what a happy little math question we have here! Let's see, if we take the square root of 51, we find that it's between the square numbers 7 and 8. The square of 8 is 64, and the square of 7 is 49. So, the square numbers that have a difference of 51 are 64 and 49.
-7 and -6 is one pair. 6 and 7 is the other, more boring pair.-7 and -6 is one pair. 6 and 7 is the other, more boring pair.-7 and -6 is one pair. 6 and 7 is the other, more boring pair.-7 and -6 is one pair. 6 and 7 is the other, more boring pair.
7 and 14 is one possible pair.
The square roots of 56 are approx -7.5 and +7.5. So any consecutive pair from [-7, +7] will do.
There are infinitely many pairs of numbers whose difference is 7. If x is any number and y = x + 7 then x and y will meet the requirements.For example, sqrt(2) and sqrt(2)+7.
They are 7 and 5
Yes.
They are both prime numbers.
They are: 2 and 7
They are 3 and 7
5 and 7