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The probability of drawing a Ace from a standard deck of 52 cards if one Ace is missing is 3 in 51, or about 0.05882. If the missing card is not an Ace, then the probability is 4 in 51, or about 0.07843.

Q: What is a probability that the selected card will be an ace if one is missing?

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Probability not ace is 1 minus probability of an ace which is 4/52. So, 1 - 4/52 is 48/52 or 12/13.

13 out of 52. _____________________ It should be 20 out of 52 if Ace is included as a number card. Not including ace the probability is 18 out of 52.

The probability of drawing two cards that are a 2 when the first card is an Ace is zero, because a two is not an Ace. They are mutually exclusive events. If this is not clear, consider the probability of rolling a seven on one roll of one six sided die. That probability is also zero - it will not happen.

Just a straight deal, the first card will be an ace 4 times out of 52, the second card will be an ace 3 times in 51. The total odds will be 12 times in 2652.However in the question posed the first card is an ace so the probability is 1 in 1, so the second card being an ace will occur 3 times in 51.In the question , the first card is ACE, and second is also an ACE. Hence probability is 1in 1.How ever the question should be framed "What is the probabilty for getting first card An ACE and also Second card as An ACE"

If you mean in one draw from a standard 52- card deck, there are 13 diamonds and ace of spades have 14 chances out of 52 for a probability of 14/52 or about 26.6923 %

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Probability not ace is 1 minus probability of an ace which is 4/52. So, 1 - 4/52 is 48/52 or 12/13.

The probability of drawing an Ace from a 52 card deck is 4/52 or 1/13.

There are total of 52 cards in a deck and 4 of those are Aces. Therefore, there are 48 card non-ace. The probability of drawing one card that is not an ace will be 48 divided by 52. The answer is 12/13.

13 out of 52. _____________________ It should be 20 out of 52 if Ace is included as a number card. Not including ace the probability is 18 out of 52.

Spade 25% Ace ~8%

513

Just a straight deal, the first card will be an ace 4 times out of 52, the second card will be an ace 3 times in 51. The total odds will be 12 times in 2652.However in the question posed the first card is an ace so the probability is 1 in 1, so the second card being an ace will occur 3 times in 51.In the question , the first card is ACE, and second is also an ACE. Hence probability is 1in 1.How ever the question should be framed "What is the probabilty for getting first card An ACE and also Second card as An ACE"

The probability of drawing two cards that are a 2 when the first card is an Ace is zero, because a two is not an Ace. They are mutually exclusive events. If this is not clear, consider the probability of rolling a seven on one roll of one six sided die. That probability is also zero - it will not happen.

From a 52 card deck, probability is 1/52.

there are 52 card and there is only 4 aces out of which only 1 ace of spade, so the probability of drawing ace of spade is 1 out of 52 or 1/52.

If you mean in one draw from a standard 52- card deck, there are 13 diamonds and ace of spades have 14 chances out of 52 for a probability of 14/52 or about 26.6923 %

The probability of drawing an Ace from a standard deck of 52 cards is 4 in 52, or 1 in 13.