If the diagonals of a quadrilateral are perpendicular to each other, then the quadrilateral is a square.
Or a kite.
A parallelogram is one of them.
Square, rhombus and a kite quadrilateral
trapezoid
A Parallelogram and a rhombus
the anser to this question is a trapiezuim as it could have right angles and its diagonals definatly do not bisect each other
A parallelogram is one of them.
No. If the diagonals of a parallelogram are congruent then it must be a rectangle (or square).
Square, rhombus and a kite quadrilateral
kite
It is an isosceles trapezoid.
Any kite or square.
trapezoid
A Parallelogram and a rhombus
the anser to this question is a trapiezuim as it could have right angles and its diagonals definatly do not bisect each other
Rhombus rhombus
The converse of the rectangle diagonal conjecture states that if the diagonals of a quadrilateral are equal in length, then the quadrilateral is a rectangle, which implies that its corners are right angles. To test if the corners of a quadrilateral are right angles, measure the lengths of the diagonals. If the diagonals are equal, you can conclude that the corners are right angles, confirming that the shape is a rectangle.
An isosceles trapezoid will have diagonals of equal length but will never contain right angles by definition. A square and rectangle will have diagonals of equal length but will contain 4 right angles. A rhombus and any other parallelogram that does not contain right angles will not have diagonals of equal length.