(75)/(100+75)x100%
= 41.28% by mass
75% of 100 = 75% * 100 = 0.75 * 100 = 75
% rate = 75%= 75/100 * 100%= 75 * 1%= 75%
75 percent as a fraction = 75%/100% = 75/100 or 3/4
It Is 75/100 (75)
3 75/100 = 15/43 75/100:= [(100 * 3)+75]/100= [300+75]/100= 375/100 or 15/4 in improper fraction
The percent of a solution is calculated by dividing the mass of the solute by the total mass of the solution, then multiplying by 100. In this case, the percent of the solution containing 2.19 g of NaCl in 75 g of the solution would be (2.19 g / 75 g) * 100 = 2.92%.
The concentration of the solution is 33.33% sugar, calculated as (25 g sugar / 75 g total mass) * 100%.
(75'C)x(1g) < (75'C)x(100g) .'. The second option has more thermal energy.
The mass of KNO3 that will crystallize out of solution can be calculated by finding the difference between the solubility limit at 75°C and the amount dissolved at 25°C. At 75°C: 100g solution contains 155g KNO3 At 25°C: 100g solution contains 38g KNO3 The amount that will crystallize out = 155g - 38g = 117g
At 40 degrees Celsius, 110 g of KNO3 is more than the solubility limit of KNO3 in 100 g of water. Therefore, the solution will be saturated because it has dissolved the maximum amount of KNO3 that it can hold at that temperature.
75% of 100 = 75% * 100 = 0.75 * 100 = 75
% rate = 75%= 75/100 * 100%= 75 * 1%= 75%
75 over 100= 75/100 in decimal= 75/100 * 100%= 75% in percent
In the given solution, there are 75 grams of water in 150 ml. This means there are 0.5 grams of water per milliliter. Therefore, in 30 ml of the solution, there would be 15 grams of water. To find the moles of water, divide the mass of water by its molar mass (16 g/mol), so in 30 ml of the solution, there would be 15/16 = 0.9375 moles of water present.
75% out of 100% is 75/100 or .75. In grade terms is a C.
75 percent as a fraction = 75%/100% = 75/100 or 3/4
5 grams of salt in 75 grams of water = 5 grams of salt in 80 grams of the solution.So the mass concentration = 5/80 = 100*5/80% = 6.25%5 grams of salt in 75 grams of water = 5 grams of salt in 80 grams of the solution.So the mass concentration = 5/80 = 100*5/80% = 6.25%5 grams of salt in 75 grams of water = 5 grams of salt in 80 grams of the solution.So the mass concentration = 5/80 = 100*5/80% = 6.25%5 grams of salt in 75 grams of water = 5 grams of salt in 80 grams of the solution.So the mass concentration = 5/80 = 100*5/80% = 6.25%