Since there are 9 members in the given set there will be 29 = 512 subsets and I have neither the time nor inclination to list all 512 of them.
A subset of the given set is any set all of whose members are members of the given set. This includes the null set.
To start off:
Null,
{1}, {3}, {6}, etc
{1,3}, {1,6}, {1,12}, etc
{1,3,6}, (1,3,12}, etc
etc
2 and 1/14 - 1 and 3/14 = 29/14 - 17/14 = 12/14 = 6/7.
If that's 12 - 8 and 1/4, the answer is 3 and 3/4
If you mean 1/14 divided by 3/12 then it is 2/7 in its simplest form
{1,2,4.7} is a proper subset of {1, 2, 3, 4, 4.7, 5}
fourteen twelves or one and a sixth. 1/4=3/12 11/12=11/12 3/12 + 11/12 = 14/12 or 1 and 2/6 or 1 and 1/3
A set is a subset of a another set if all its members are contained within the second set. A set that contains all the member of another set is still a subset of that second set.A set is a proper subset of another subset if all its members are contained within the second set and there exists at least one other member of the second set that is not in the subset.Example:For the set {1, 2, 3, 4, 5}:the set {1, 2, 3, 4, 5} is a subset set of {1, 2, 3, 4, 5}the set {1, 2, 3} is a subset of {1, 2, 3, 4, 5}, but further it is a proper subset of {1, 2, 3, 4, 5}
Factors of 12: 1, 2, 3, 4, 6 and 12. Factors of 14: 1, 2, 7 and 14.
1, 2, 3, 4, 6, 12 1, 2, 7, 14 1, 3, 5, 15
2 and 1/14 - 1 and 3/14 = 29/14 - 17/14 = 12/14 = 6/7.
An improper subset is identical to the set of which it is a subset. For example: Set A: {1, 2, 3, 4, 5} Set B: {1, 2, 3, 4, 5} Set B is an improper subset of Set Aand vice versa.
If that's 12 - 8 and 1/4, the answer is 3 and 3/4
An improper subset is identical to the set of which it is a subset. For example: Set A: {1, 2, 3, 4, 5} Set B: {1, 2, 3, 4, 5} Set B is an improper subset of Set Aand vice versa.
If you mean 1/14 divided by 3/12 then it is 2/7 in its simplest form
{1,2,4.7} is a proper subset of {1, 2, 3, 4, 4.7, 5}
1 3/4 + 5 5/12 4x3=12 3x3=9 9/12 + 5/12 14/12 + 1 2/12 7 2/12 or 6 14/12
Factors of 12: 1, 2, 3, 4, 6, 12Factors of 14: 1, 2, 7, 14Factors of 18: 1, 2, 3, 6, 9, 18GCF (12, 14, 18) = 2
1/14 + 2/35 + 3/12 = 53/140