27, remainder 1
1.1739
No, 27 divided by 18 equals 1 with a remainder of 9.
1.9643
Divide the number by 5, and the remainder in that division is the 'ones' (50) digit. Take that quotient (without the remainder) and divide by 5. The remainder is the 'fives' (51) digit. Continue dividing until you have zero, with a remainder and that will be the leftmost digit. Example 27 (base ten) to base 5: 27 / 5 = 5, remainder 2 5 / 5 = 1, remainder 0 1 / 5 = 0, remainder 1 so 102 (base 5) is the same as 27 (base 10). You can check: 1 is in the (52=25) place, and the 2 is in the 'ones' place. So (1*25) + (0*5) + (2*1) = 27
If you are working with a division problem r=remainder. e.g. If you divide 27 by 4 you get 6 r 1 which means 6 remainder 1. I hope I helped : D
13.5
It would be 27.(1/27). So.... 27.03703703703.
27.027
27, remainder 1
1.1739
27 with remainder 1.
If the question means what is 54 in binary then this can be solved by continually dividing by 2 and noting the remainder. 54 ÷ 2 = 27 remainder 0 27 ÷ 2 = 13 remainder 1 13 ÷ 2 = 6 remainder 1 6 ÷ 2 = 3 remainder 0 3 ÷ 2 = 1 remainder 1 1 ÷ 2, final remainder 1 Reading the remainder values from bottom to top gives 110110 which is the binary equivalent of 54.
1, 3, 9 and 27.
No, 27 divided by 18 equals 1 with a remainder of 9.
1.9643
Divide the number by 5, and the remainder in that division is the 'ones' (50) digit. Take that quotient (without the remainder) and divide by 5. The remainder is the 'fives' (51) digit. Continue dividing until you have zero, with a remainder and that will be the leftmost digit. Example 27 (base ten) to base 5: 27 / 5 = 5, remainder 2 5 / 5 = 1, remainder 0 1 / 5 = 0, remainder 1 so 102 (base 5) is the same as 27 (base 10). You can check: 1 is in the (52=25) place, and the 2 is in the 'ones' place. So (1*25) + (0*5) + (2*1) = 27