abc = 183.if abc + abc = cdd and d = 6, then:abc + abc + c66So, looking at the units:c + c = 6 possibly plus carry⇒ c = 3 (no carry) or c = 8 (carry)Looking at the tens:b + b + possible_carry_from_units = 6⇒ 2b + possible_carry = 62b is even, 6 is even, so the possible_carry must be even.The possible_carry is either 0 or 1; 1 is odd, so it must be 0, so c must be 3 (c = 3).This leave 2b = 6 possibly plus carry⇒ b = 3 (no carry) or b = 8 (carry)Looking at the hundreds:a + a + possible_carry_from_tens = c = 3 (as just found)⇒ 2a + possible_carry = 32b is even, 3 is odd, so the possible_carry must be odd.The possible_carry is either 0 or 1; 1 is odd, so it must be 1, so b must be 8 (b = 8).This leaves 2a + 1 = 3⇒ 2a = 2⇒ a = 1Making the number abc = 183.
6+1 equals 7. Plus 3 equals 10. Plus 4 equals 14.
2.5 plus 6 plus 3 equals 2.5 plus 6 plus 3
(6 plus 6) divided by (6 plus 6) times 6 equals 6
6.
abc = 183.if abc + abc = cdd and d = 6, then:abc + abc + c66So, looking at the units:c + c = 6 possibly plus carry⇒ c = 3 (no carry) or c = 8 (carry)Looking at the tens:b + b + possible_carry_from_units = 6⇒ 2b + possible_carry = 62b is even, 6 is even, so the possible_carry must be even.The possible_carry is either 0 or 1; 1 is odd, so it must be 0, so c must be 3 (c = 3).This leave 2b = 6 possibly plus carry⇒ b = 3 (no carry) or b = 8 (carry)Looking at the hundreds:a + a + possible_carry_from_tens = c = 3 (as just found)⇒ 2a + possible_carry = 32b is even, 3 is odd, so the possible_carry must be odd.The possible_carry is either 0 or 1; 1 is odd, so it must be 1, so b must be 8 (b = 8).This leaves 2a + 1 = 3⇒ 2a = 2⇒ a = 1Making the number abc = 183.
No.
No! It equals 15, but 9-6=3.
6+1 equals 7. Plus 3 equals 10. Plus 4 equals 14.
2.5 plus 6 plus 3 equals 2.5 plus 6 plus 3
6 plus 7 plus 8 equals 6 plus 8 plus 7, what property is that?That is the associative property.
(6 plus 6) divided by (6 plus 6) times 6 equals 6
6.
28
it equals 70
14
4 x 6 = 24 lieng