The answer is 47-13=34
In base 10, all numbers whose last digit is a 5 or a 0
To find the LCM of 95 and 152, you first need to split these numbers into their prime factors: 95 = 5x19 152 = 2x2x2x19 The next step is to identify any common prime factors. In this case both have 19 as a prime factor. We only need to count this common number once, but gather all the other numbers: 5,19,2,2,2 And find the product: 5x19x2x2x2=760 So the LCM of 95 and 152 is 760.
The difference is that all whole numbers are decimal numbers, but not all decimal numbers are whole numbers. For example a whole number such as 1 is a decimal number but a decimal number such as 1.5 is not a whole number.
They are all composite numbers whose GCF is 1
The answer is 47-13=34
15,656
To be honest, there's only one number in all of math that's equal to 152.The number is . . . . . wait for it . . . . . 152 .
This is easily solved by using two equations in 2 unknowns and solving the system. x + y = 111 x - y = 43 If have not yet had the pleasure of studying algebra and the answer is important to you, you could hope the numbers are positive integers and try all pair of numbers whose sum is 43: 1,42 2,41 3,40 and so on, until you find a pair whose difference is 43.
Yes. All whole numbers greater than two and ending in 2 are composite.
Write three numbers whose sum is 10 in all horizontal vertical and diagonal?
There is no difference because all integers or whole numbers are considered to be rational numbers.
In base 10, all numbers whose last digit is a 5 or a 0
I would list all the factors of 480 (as pairs of numbers whose product is 480). Then find two pairs of numbers (L1,W1 and L2,W2) satisfying these properties. (It won't take long, since there are at most sqrt(480) (rounded down) pairs of numbers whose product is 480, ie. just try the numbers 1,2,3,...,21.) Hope that helps!
Use a direct proof; Suppose Tom minimises the largest difference between two numbers. For this to be true, Tom must pick consecutive numbers. If Tom picks 10 consecutive numbers the maximum difference must be 9. Given that tom picks one more number, there must be two numbers who differ by 10 for all selections.
Hi
All natural numbers are rational numbers. No irrational numbers are natural numbers.