sometimes, the altitude of isosceles triangles resting on their base and equilateral triangles are angle bisectors
they are the same because the triangles side is equal
It must be an obtuse angled triangle.
5.408 cm.
Area of triangle = ½ base x altitude. Regular hexagon is 6 equal triangles so Area= 3 x base x altitude
sometimes, the altitude of isosceles triangles resting on their base and equilateral triangles are angle bisectors
they are the same because the triangles side is equal
It must be an obtuse angled triangle.
5.408 cm.
I suppose by "length of a triangles altitude" you mean height. The height of the triangle in question cannot be determined from the information given. In order to determine the height of the triangle, two dimensions must be known.
If you know the hypotenuse and the base then use Pythagoras' theorem to find the altitude
For the equilateral triangle in Euclidean space(i.e, the triangles you see in general) median is the same as its altitude. So, both are of equal length.
In geometry, a perpendicular segment that connects a vertex to its opposite side is the altitude of a triangle. Triangles have three altitudes, according to this definition for altitude.
Area of triangle = ½ base x altitude. Regular hexagon is 6 equal triangles so Area= 3 x base x altitude
Only if the angles of the triangle are 90, 45, and 45.
Not necessarily. That only happens in isosceles and equilateral triangles.
actually it's a2+b2=c2 the altitude is a or b and can be found by c2/a2*=b2* * a2 and b2 are interchangeable. by the way this only works with right triangles.