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Thousands digit is 8 which is two more than the hundreds digit?
that means the hundreds digit is 6
What digit is in the hundreds place in the number 89742.165?
Ten Thousands - 8 Thousands - 9 Hundreds - 7 Tens - 4 Ones - 2 Tenths - 1 Hundredths - 6 Thousandths - 5
If You are thinking of a 4 digit number that has twice as many thousands as ones twice as many ones as hundreds a twice as many hundreds as tens what is your number?
Oh, dude, that's like a math riddle straight out of a textbook. So, let's break it down: if we have twice as many thousands as ones, that means the thousands digit has to be 8 (since 8x2=16). Then, twice as many ones as hundreds means the ones digit is 2 (since 2x2=4). And finally, twice as many hundreds as tens means the hundreds digit is 4 (since 4x2=8). So, the number is 8422. Math can be fun, right?
What is the greatest six digit even number where the ten thousand digit is twice tens digit hundred thousand digit is more than 6 the thousands digit is divided by ones digit and no digit repeated?
In order to get the greatest number we want to try and get the biggest possible numbers in the hundred thousands, ten thousands and thousand places. There is no rule against the hundred thousands digit being 9 so it must be 9. The ten thousand digit needs to be twice the tens so it must be 8 while the tens is 4. The thousands digit is divided by the units, and the number is even. So thousands must be 6 and the units must be 2. Thus the hundreds must be 7. The number is 986,742
What are the 4 digit numbers possible from 0-9 with no number repeated?
There are 4536 of them and I have neither the time nor the inclination to list them. This assumes the starting digit is not 0. If 0 is allowed as the first digit, there will be 5040 such numbers. Since each digit is used only once, this is a problem without replacement means that an outcome cannot be included more than once. In this case, the first event does affect the possibilities for the second event. These event are dependent. So the number could have any of these forms: 1_ _ _ , 2_ _ _ , 3_ _ _ , 4_ _ _ , 5_ _ _ , 6_ _ _ , 7_ _ _ , 8_ _ _ , 9_ _ _ . There are 9 choices for the thousands digit: 1, 2, 3, 4, 5, 6, 7, 8, or 9. After the thousands digit is chosen, 9 choices are left for the hundreds digit After the hundreds digit is chosen, 8 choices are left for the tens digit. After the tens digit is chosen, 7 choices are left for the units digit. Then, we have (9 * 9 * 8 * 7) 4536 numbers.
Thousands digit is 8 which is two more than the hundreds digit?
that means the hundreds digit is 6
How many thousands are there in Ten Thousands?
There are 9000 4 digit numbers Find 4 digit numbers that are all different from 1 find 4 digit numbers that are all different from 1 The thousands digit has 8 ways to choose, hundreds, tens, and units all have 9 ways => there are 8 x 9 x 9 x 9 = 5832 digits => 4 digit numbers contain at least 1 digit 1 = number of 4 digit numbers , the number of 4 digit numbers is different by digit 1 =9000 - 5832 = 3168 numbers
The thousands digit is 8 which is two more than the hundreds dight?
86xx
The thousands digit of a 4-digit number is 4 greater than the hundreds digit The tens digit is 2 times the Thousands digit The ones digit is one-half the thousands digit What is the number?
4082 Since the tens digit is 2 times the thousand digit, it must be an even digit. So it can be 8, 6, 4, or 2. But, the thousands digit is 4 greater than the hundred digit. So that the hundred digit must be 0, the thousands digit must be 4, the hundreds digit must be 8, and the ones digit must be 2.
How many 4-digit numbers are possible if the hundreds digit is 8 and if repetition of digits is allowed?
-4
What digit is in the hundreds place in the number 89742.165?
Ten Thousands - 8 Thousands - 9 Hundreds - 7 Tens - 4 Ones - 2 Tenths - 1 Hundredths - 6 Thousandths - 5
You are an 8-digit number the digit in the thousands place is the result of dividing 64 by 8?
No, the digit in that position will arise from a whole range of possibilities. If N is a (integer) number taken at random then the number in the thousands place could be anything equally. In particular, if you divide 88888888 by 8 the digit in the thousands place comes from dividing 8 by 8. 64/8 is 8 so that is the digit in the thousands position. So you could have any one of numbers like xxxx8xxx where each x could be any digit, eg 11118111, 12348765, etc.
If You are thinking of a 4 digit number that has twice as many thousands as ones twice as many ones as hundreds a twice as many hundreds as tens what is your number?
Oh, dude, that's like a math riddle straight out of a textbook. So, let's break it down: if we have twice as many thousands as ones, that means the thousands digit has to be 8 (since 8x2=16). Then, twice as many ones as hundreds means the ones digit is 2 (since 2x2=4). And finally, twice as many hundreds as tens means the hundreds digit is 4 (since 4x2=8). So, the number is 8422. Math can be fun, right?
How do you solve place value of an 8 digit number?
The places are always the same no matter what the digits are. The value is obtained by multiplying the place times the digit. Starting from the right, the places in an 8-digit number are ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions and ten millions.
What is the greatest six digit even number where the ten thousand digit is twice tens digit hundred thousand digit is more than 6 the thousands digit is divided by ones digit and no digit repeated?
In order to get the greatest number we want to try and get the biggest possible numbers in the hundred thousands, ten thousands and thousand places. There is no rule against the hundred thousands digit being 9 so it must be 9. The ten thousand digit needs to be twice the tens so it must be 8 while the tens is 4. The thousands digit is divided by the units, and the number is even. So thousands must be 6 and the units must be 2. Thus the hundreds must be 7. The number is 986,742
Which digit is in the thousands place in 4968123?
Which digit is in the thousands place in 4,968,123?
What are the 4 digit numbers possible from 0-9 with no number repeated?
There are 4536 of them and I have neither the time nor the inclination to list them. This assumes the starting digit is not 0. If 0 is allowed as the first digit, there will be 5040 such numbers. Since each digit is used only once, this is a problem without replacement means that an outcome cannot be included more than once. In this case, the first event does affect the possibilities for the second event. These event are dependent. So the number could have any of these forms: 1_ _ _ , 2_ _ _ , 3_ _ _ , 4_ _ _ , 5_ _ _ , 6_ _ _ , 7_ _ _ , 8_ _ _ , 9_ _ _ . There are 9 choices for the thousands digit: 1, 2, 3, 4, 5, 6, 7, 8, or 9. After the thousands digit is chosen, 9 choices are left for the hundreds digit After the hundreds digit is chosen, 8 choices are left for the tens digit. After the tens digit is chosen, 7 choices are left for the units digit. Then, we have (9 * 9 * 8 * 7) 4536 numbers.
