n = number.
n + 5
====
The algebraic expression for "6 more than a number" can be represented as ( x + 6 ), where ( x ) is the variable representing the unknown number. This expression indicates that you take the number ( x ) and add 6 to it.
The algebraic expression for "five more than three times some number" is 3x + 5, where x represents the unknown number.
The algebraic expression would be 8n + 3, where n represents the unknown number.
n + 7
2x + 5
The algebraic expression for "6 more than a number" can be represented as ( x + 6 ), where ( x ) is the variable representing the unknown number. This expression indicates that you take the number ( x ) and add 6 to it.
Let the number be a a + 8
x+29
what us the algebraic expression for 359 more than Z
The algebraic expression for "five more than three times some number" is 3x + 5, where x represents the unknown number.
The algebraic expression would be 8n + 3, where n represents the unknown number.
2x + 5
The required algebraic expression is a + 33.
n + 7
n + 25 =====
n + 4
Let the number be x and so the expression would be: x+20