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First consider triangles ACD and BCD. They share a common base, CD, and their height is the distance between the parallel lines AB and CD. Consequently, area(ACD) = area(BCD) . . . . . . . . eqn 1 But ACD = AOD + OCD and BCD = BOC + OCD So area(ACD) = area(AOD) + area(OCD) and area(BCD) = area(BOC) + area(OCD) Substituting in eqn 1, area(AOD) + area(OCD) = area(BOC) + area(OCD) area(AOD) = area(BOC)
Right angle, obtuse angle, acute angle, supplementary angle, complementary angle, interior angle, exterior angle, adjacent angle
The angle of incidence
the angle of incidence is the initial ray angle and the angle of reflection is the reflected ray angle
It is a reflex angle