equation works for n = 0 and n = 1 as factors are n and n - 1
N = 1
There are infinitely many possibilities. One of these is n+1 = 0
n = 1/2
t(n) = 1 + 3n (n = 1, 2, 3, ... )
equation works for n = 0 and n = 1 as factors are n and n - 1
Through a process called solving the equation. How do I solve the equation
N = 1
If you want to sum up numbers 1 to N, you can do it this way. Sum = (N+1)*(N/2).The reason this works: say you want to sum up 1 through 10. You have 10+1, 9+2, ..., 6+5. Each of these equals 11 [N+1]. You added 11 five times (N/2). Sum of 1 to 102 = (102+1)*(102/2) = 103*51 = 5253. You can check it by summing up the numbers with a spreadsheet.
It is not an equation because it has no equality sign but it means xn squared-nx
There are infinitely many possibilities. One of these is n+1 = 0
A linear equation. In n-dimensional space, it is of the form A(0) + A(1)X(1) + ... + A(n-1)X(n-1) + A(n)X(n) = 0 where A(0), A(1), ... A(n) are coefficients and X(1), ... X(n) are the variables. Normally the 0, 1, ... n would be written as suffices but this browser does not support such mathematically essential features! In 2-dimensional space, the equation becomes A(0) + A(1)X(1) + A(2)X(2) = 0 If you rewrite X(1) = X and X(2) = Y, you get A(0) + A(1)X + A(2)Y = 0 which can be rearranged to A(2)Y = -A(1)X + A(0) Then, dividing through by A(2) and writing m = -A(1)/A(2) and c = A(0)/A(2) gives Y = mX + c - the slope-intercept form of the equation of a straight line in 2 dimensions.
To solve the equation -n = 7, you need to isolate the variable n. To do this, you can multiply both sides of the equation by -1 to get n by itself. By multiplying both sides by -1, you get n = -7. Therefore, the solution to the equation -n = 7 is n = -7.
You have one linear equation in two unknown variables: A and n. There can be no solution.
that is an impossible question as n isn't in the equation
0.5
If you were trying to find 1+2+3+4+5+...+(n-1)+n the formula would be (n*(n+1))/2