-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
-9
4(n+12)
(x-12)*4 in a computer language, In algebra, 4(x-12) = (You need to say what the equation is )
Depending on where exactly the commas are in the statement, the equation will be different. Based on the exact punctuation and wording of the question, the equation is: 3a+4b=(x+y)/7-12
3(x + 12)
It is 1+6+2+3 = 12.
-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
-9
4(n+12)
(x-12)*4 in a computer language, In algebra, 4(x-12) = (You need to say what the equation is )
Depending on where exactly the commas are in the statement, the equation will be different. Based on the exact punctuation and wording of the question, the equation is: 3a+4b=(x+y)/7-12
Start by setting up an equation. Use x for the integer. The equation would be: x/-3=12+-20 Find the sum of 12 and -20 which is -8. Therefore the equation would now be: x/-3=-8 Multiply -8 by -3 which equals 24. Therefore x=24 Plug it back into the equation to check that it works: 24/-3=12+-20 24/-3=-8 -8=-8 Thefore 24 is the integer that when divided by -3 it equals the sum of 12 and -20.
A product is the answer of a multiplication equation. A sum is the answer of an addition equation.
The answer to the equation 5 plus 7 is 12. When numbers are being added, the answer is called the sum.
x + y = 22 x - y = 12 x = 17 y = 5
Let 'S' represent the sum. Then the equation isS = 198 + 65