a centimetre is a hundredth of a metre so the sum is 100/9. this is 11 and 1/9
81 cm
For example, 11, -1, -1.
According to the given length & width, the diagonal must be 15 cm.So,2X - 11 = 152X = 26X = 13
Area = 0.5*(9 + 3)*11 = 0.5*12*11 = 66 sq cm
45 cm.
The density of the object is 9 g/cm^3.
Is there a seven if so 7 if not 9 and a half
4*9 = 36 square cm
A pentagon.
Using Hooke's Law, we can set up a proportion to solve for the mass of the object stretching the spring 9 cm. Since the force required to stretch a spring is directly proportional to the distance stretched, an object with a mass of 6 kg would stretch it to 9 cm.
There are hundreds of possibileties but I will give you an example: 3 1/4 + 6 3/4
a centimetre is a hundredth of a metre so the sum is 100/9. this is 11 and 1/9
9 feet 7 inches = 292.1 centimeters.Algebraic Steps / Dimensional Analysis Formula115in* 2.54 cm1 in= 292.1cm
9 feet = 274.32 centimetersThere are 30.48 centimetres in one inch. Therefore, 9 feet is equal to 9 x 30.48 = 274.32 centimetres.
To find the area (A) of any rectangle, we multiply the length (l) by the width (w). In the case of a rectangle that is 11 cm by 9 cm, we do this:Arectangle = l x w = 11 cm x 9 cm = 99 cm2or 99 square centimeters.
About the size of a cornish hen. or a mocking bird