A common multiple of 14 and 20 is 140. As a matter of fact, it is the least common multiple.
One mathematical fact about number 23 is that number 23 is an odd number. Another mathematical fact about number 23 is that number 23 is prime number.
Same as hindsight is 20/20.
20 / 0.2 = 100. Therefore, the number that 20 is 20 percent of, is 100.
8-7
20. The fact that it is an ion has nothing to do with the number of electrons.
A common multiple of 14 and 20 is 140. As a matter of fact, it is the least common multiple.
You can add 0 to 20 to get 20, or 10 to 20 and get 30 (In fact, you can try any multiple of 10). Otherwise, there are no other values you can add to 20 to get a 0 for the number in front of the decimal place.
LCM is the smallest number a number can go into. Since 4 multiplied by 5 is 20 and 20 is a multiple of 100 and 50 can go into that, along with the fact 20 can't go into 50 evenly, the least common multiple of 4 and 50 is 100.
One mathematical fact about number 23 is that number 23 is an odd number. Another mathematical fact about number 23 is that number 23 is prime number.
if you want the whole number, multiply 20 by 7. 20+20+20+20+20+20+20=140
Same as hindsight is 20/20.
20 / 0.2 = 100. Therefore, the number that 20 is 20 percent of, is 100.
8-7
You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...
1)strong number1 declare2 n number(3);3 fact number(3):=1;4 rem number(3);5 m number(3);6 sum1 number(3):=0;7 begin8 dbms_output.put_line('enter a number');9 n:=&n;10 m:=n;11 while(n>0) loop12 rem:=mod(n,10);13 for i in 1..rem loop14 fact:=fact*i;15 end loop;16 sum1:=sum1+fact;17 n:=trunc(n/10);18 fact:=1;19 end loop;20 if(sum1=m) then21 dbms_output.put_line(m' IS STRONG NUMBER');22 else23 dbms_output.put_line('IT IS NOT STRONG NUMBER');24 end if;25* end;
20 is a composite number