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Several options:Draw it and measure the missing side.Use coordinate geometry. You can draw the base and two of the sides since you know the angles that these lines make and their lengths. You therefore know their upper end points and so calculating the length of the fourth side is trivial.Consider the triangle ABC. Sides AB and BC are known as is angle ABC. So you can use the sine rule to calculate AC and angles CAB and ACB. Angle DAB is known so angle DAC = DAB - CAB, angle ACD = BCD - ACB. In triangle ACD, two angles are known so all three are known. Use the sine rule again to find CD.
AX bisects angle DAB so angles DAX and XAB are equal. .. .. .. .. .. .. .. .. (i)DA is parallel to CB and AX is an intercept.So angle DAX and AXB are alternate angles and therefore angles DAX and AXB are equal.Therefore, by (i) angles XAB and AXB are equal.Thus triangle BAX is isoscelestherefore AB = BX.BX = 1/2*BC = 1/2*AD (since ABCD is a parallelogram).Therefore AB = BX = AD/2.
Right angle, obtuse angle, acute angle, supplementary angle, complementary angle, interior angle, exterior angle, adjacent angle
The angle of incidence
the angle of incidence is the initial ray angle and the angle of reflection is the reflected ray angle