about 12,589,255,298,531,900,000,000,000,000,000,000,000,000,000
51*7=357
51/7 = 72/7
51
7 x 51 = 357
7.2857
51
51/21 = 17/7 = 23/7
51 minus 27 3/7 = 23 4/7
-58
51 > 0. Since the sum 14 is positive, the factors of 51 are both positive. The problem is that 51 = 3*17 and 3 + 17 = 20 ≠ 14. But we are lucky that 14 = 7 + 7. So wee can use the difference of the squares such as (7 - A)(7 + A) = 49 - A2 = 51, where -A2 = 2 = -(i√2)2 . Thus, the numbers are 7 - i√2 and 7 + i√2. or algebraically, x + y = 14; y = 14 - x xy = 51 x(14 - x) = 51 -x2 +14x = 51 x2 -14x = -51 x2 -14x + 72 = -51 + 49 (x - 7)2 = -2 x - 7 = ± √-2 x = 7 ± i√2
1+4+7+10+13+16= 51 (Why don't u check your calculator)