You may have noticed a small sketch or drawing right next to the question,
right there on the page where you copied it from. That little drawing or sketch
is absolutely necessary in order to answer the question. There's no way to answer
the question without it.
The length of the arc of ABC is 22pi. You can get this answer by completing this equation 330/360*24pi, which will give you 22pi.
This is your lucky day ! Watch now, as the Great and Powerful WA Contributorsolves your problem and answers your question without ever seeing the drawingthat's supposed to go along with it, and with no idea what 'BC' and 'ab' are . . .-- A whole circle has a central angle of 360 degrees.-- A whole circle with a radius of 10 has a circumference of [ (2 pi) x (radius) ] = 20 pi .-- A slice of cake with a central angle of 120 degrees is 1/3 of a circle.-- The arc at the fat end of the slice is 1/3 of the full circle's circumference = 20 pi/3 = 20.944 (rounded)-- Just in case 'BC' is the long arc, then its length is the other 2/3 of the whole circle= 2 x 20 pi/3 = 41.888 (rounded)Pay no attention to that old man behind the curtain.
Yes. If two intersecting lines form the angles A, B, C and D (in rotational order) then AB, BC, CD and DA are pairs of supplementary angles.
To prove that the base angles of an isosceles trapezoid are congruent, consider an isosceles trapezoid ( ABCD ) with ( AB \parallel CD ) and ( AD \cong BC ). By the properties of parallel lines, the angles ( \angle DAB ) and ( \angle ABC ) are consecutive interior angles formed by the transversal ( AD ) and ( BC ), respectively, thus ( \angle DAB + \angle ABC = 180^\circ ). Similarly, the angles ( \angle ADC ) and ( \angle BCD ) also sum to ( 180^\circ ). Since ( AD \cong BC ) and the trapezoid is isosceles, the two pairs of opposite angles must be equal, leading to ( \angle DAB \cong \angle ABC ) and ( \angle ADC \cong \angle BCD ), proving that the base angles ( \angle DAB ) and ( \angle ABC ) are congruent.
Since the right angle is not identified, the answer is either sqrt(84) or sqrt(116) units.
The 2nd century BC.
the answer is 98
100 degrees :)
26.17
22
If angle 1 is the central angle BOC which intersects the arc BC, then 2x + 3 = 5x - 17 because a central angle has the same numbers of degrees as the arc it intercepts. 2x + 3 = 5x - 17 20 = 3x 20/3 = x Thus, x is 6 2/3 degrees.
She was born in the year AD1412.
The year after 20 BC is 19 BCE.
The measure of five is 5.
If the sides of the triangle are 20 and 15 then by using Pythagoras' theorem the length of the hypotenuse works out as 25 units of measurement.
Yes
The measure of five is 5.