The area of a hexagon with a perimeter of 24 feet is about 41.6 square feet.
The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
The edge length of a regular hexagon with a perimeter of 24 cm is 24/6 = 4 cm
24 cm
24 units
4cm
The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
The perimeter is 24 feet.
. What is the greatest area possible enclosed by a quadrilateral with a perimeter of 24 feet?
The edge length of a regular hexagon with a perimeter of 24 cm is 24/6 = 4 cm
Area = 8*24 =192 square feet Perimeter = 24+24+8+8 = 64 feet
24 cm
24 units
4cm
4cm
The area of the square would be 36 square feet and the perimeter is basically four times the side, because a square has equal sides so the perimeter would be 24 feet. \
A regular hexagon is made up of six congruent equilateral triangles, the area of an equilateral triangle can be computed using the formula s2(√3)/4, where s is the length of one side of the triangle. Since the hexagon comprises 6 equilateral triangles, each triangle has an area of 24/6 = 4. Solving for 4 = s2(√3)/4 gives s = 4/(3^(1/4)). Since one side of the triangle is also one side of the hexagon, we can multiply this by 6 to find the perimeter of the hexagon: 6 × 4/(3^(1/4)) = 8×3^(3/4) ≈ 18.23 Therefore, the perimeter of a hexagon whose area is 24 is 8×3^(3/4) or approximately 18.236056455638221135948506015709
To find the perimeter of a rectangle, you add up all the sides. In this case, the room is 24 feet long and 15 feet wide. So, the perimeter would be 24 + 24 + 15 + 15 = 78 feet.