There is not suficient information. A measure of the vertical height is required - either implicit or explicit.
If you think of a rhombus as 4 sticks of 7 cm hinged at the vertices, you can change the shape to a square (area = 49 sq cm) or squash it right down so that the area gets as close to 0 as you wish.
You can imagine it to be the area of a square figure (four equal sides and angle beween adjacent sides is 90 degrees) whose side is7 cm
Two sides of a triangle are not sufficient to determine its area.
24.5 cm2 - Simply multiply the two known values together !
A rhombus is a quadrilateral whose four sides all have the same length. I think you are describing a trapezoid - a figure with only one set of parallel sides.The formula for finding the area of a trapezoid is:A = (s1 + s2) / 2 x h where s1 and s2 are the parallel sides and h is the height.Basically this is our old "base times height" formula, but since our bases (the parallel sides) are not equal, we add them together and divide by 2 to get the average that we multiply times the height.For your trapezoid the equation looks like this:A = (15 + 17) x 7 /2A = 32 x 7 /2A = 112 cm2
Since there are five numbers given it is assumed that the figure in question is a pentagon. Unfortunately, a triangle is the only polygonal shape that is rigid. A pentagon, with all five sides of known lengths is not rigid - it can be flexed in the same way that a square can be flexed into a rhombus. The area of a rhombus can take any value from 0 up to the value of the square: the exact value is indeterminate. Similarly for a pentagon.
The area of a hexagon with 7cm sides is approximately 127.31cm2
Area 51.
You can imagine it to be the area of a square figure (four equal sides and angle beween adjacent sides is 90 degrees) whose side is7 cm
Two sides of a triangle are not sufficient to determine its area.
Too many dimensions have been given to work out an answer.
A triangle with side a: 7, side b: 7, and side c: 5 cm has an area of 16.35 square cm.
The perimeter is the addition of the all the sides of the shape. For example if a rectangle has two sides which are 4cm and two sides which are 7cm, then the perimeter will be 4cm+4cm+7cm+7cm. The perimeter would therefore be 22cm. The area of a shape is gotten by multiplying the length and breadth of the shape. For example, in a rectangle witrh the same measurements above, the area will be 4cm x 7cm and that would 28cm. You have to use the square sign but I can't do that here.
area= 7cm x 7cm = 49cm^2
6 sides therefore 6(l*b) l=7cm b=7cm 6(7*7)=294cm
Well, darling, to find the area of a shape, you need to know the shape itself! If those numbers represent the sides of a rectangle, you can pair them up to find the length and width. Then, just multiply the length by the width to get the area. So, in this case, the area would be 36 square centimeters.
24.5 cm2 - Simply multiply the two known values together !
A rhombus is a quadrilateral whose four sides all have the same length. I think you are describing a trapezoid - a figure with only one set of parallel sides.The formula for finding the area of a trapezoid is:A = (s1 + s2) / 2 x h where s1 and s2 are the parallel sides and h is the height.Basically this is our old "base times height" formula, but since our bases (the parallel sides) are not equal, we add them together and divide by 2 to get the average that we multiply times the height.For your trapezoid the equation looks like this:A = (15 + 17) x 7 /2A = 32 x 7 /2A = 112 cm2