There is not suficient information. A measure of the vertical height is required - either implicit or explicit.
If you think of a rhombus as 4 sticks of 7 cm hinged at the vertices, you can change the shape to a square (area = 49 sq cm) or squash it right down so that the area gets as close to 0 as you wish.
You can imagine it to be the area of a square figure (four equal sides and angle beween adjacent sides is 90 degrees) whose side is7 cm
Two sides of a triangle are not sufficient to determine its area.
24.5 cm2 - Simply multiply the two known values together !
A rhombus is a quadrilateral whose four sides all have the same length. I think you are describing a trapezoid - a figure with only one set of parallel sides.The formula for finding the area of a trapezoid is:A = (s1 + s2) / 2 x h where s1 and s2 are the parallel sides and h is the height.Basically this is our old "base times height" formula, but since our bases (the parallel sides) are not equal, we add them together and divide by 2 to get the average that we multiply times the height.For your trapezoid the equation looks like this:A = (15 + 17) x 7 /2A = 32 x 7 /2A = 112 cm2
Since there are five numbers given it is assumed that the figure in question is a pentagon. Unfortunately, a triangle is the only polygonal shape that is rigid. A pentagon, with all five sides of known lengths is not rigid - it can be flexed in the same way that a square can be flexed into a rhombus. The area of a rhombus can take any value from 0 up to the value of the square: the exact value is indeterminate. Similarly for a pentagon.
The area of a hexagon with 7cm sides is approximately 127.31cm2
Area 51.
You can imagine it to be the area of a square figure (four equal sides and angle beween adjacent sides is 90 degrees) whose side is7 cm
Two sides of a triangle are not sufficient to determine its area.
Too many dimensions have been given to work out an answer.
A triangle with side a: 7, side b: 7, and side c: 5 cm has an area of 16.35 square cm.
The perimeter is the addition of the all the sides of the shape. For example if a rectangle has two sides which are 4cm and two sides which are 7cm, then the perimeter will be 4cm+4cm+7cm+7cm. The perimeter would therefore be 22cm. The area of a shape is gotten by multiplying the length and breadth of the shape. For example, in a rectangle witrh the same measurements above, the area will be 4cm x 7cm and that would 28cm. You have to use the square sign but I can't do that here.
area= 7cm x 7cm = 49cm^2
6 sides therefore 6(l*b) l=7cm b=7cm 6(7*7)=294cm
Since there are 4 lengths given, the shape could be a quadrilateral. Unfortunately, the lengths of the sides is not enough information to determine the shape of a quadrilateral. As an illustration, consider a square of sides 10 cm. Its area is 100 cm2. But it can be "distorted" into a rhombus with the same sides but the area can be reduced to as close to 0 as you like. Four linear measures could also mean that it is a 4-dimensional cuboid in hyperspace or some other shape in 2 or 3 dimensions. But since these shapes cannot be determined, it is not possible to find an answer to the question.
24.5 cm2 - Simply multiply the two known values together !
A rhombus is a quadrilateral whose four sides all have the same length. I think you are describing a trapezoid - a figure with only one set of parallel sides.The formula for finding the area of a trapezoid is:A = (s1 + s2) / 2 x h where s1 and s2 are the parallel sides and h is the height.Basically this is our old "base times height" formula, but since our bases (the parallel sides) are not equal, we add them together and divide by 2 to get the average that we multiply times the height.For your trapezoid the equation looks like this:A = (15 + 17) x 7 /2A = 32 x 7 /2A = 112 cm2