40
199998
100*99999 = 9999900100*99999 = 9999900100*99999 = 9999900100*99999 = 9999900
99999 - (-999999) = 99999 + 999999 = 1099998
99999+1
import random random.randrange(1, 99999) #Set range from 1 to 99999
40
It would stay the same
199998
10,000,800,001 is 99999 times 99999.
100*99999 = 9999900100*99999 = 9999900100*99999 = 9999900100*99999 = 9999900
99999 - (-999999) = 99999 + 999999 = 1099998
99999+1
There are 3598 numbers between 10000 and 99999 which are divisible by 25. They are elements of the set of numbers of the form 25*k, where k is an integer between 41 and 3999 (inclusive).
3456 - 99999 = -96,543
2.250388e+167
99,999 + 99,999 = 199,998