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Sure, here are two examples of complex fractions: **Example 1**: [ \frac{\frac{3}{4}}{\frac{5}{6}} ] This is a complex fraction where the numerator is (\frac{3}{4}) and the denominator is (\frac{5}{6}). **Example 2**: [ \frac{\frac{2x + 1}{3}}{\frac{7}{2x - 4}} ] This is a complex fraction where the numerator is (\frac{2x + 1}{3}) and the denominator is (\frac{7}{2x - 4}). In both examples, the fractions within the numerator and the denominator make the overall fraction complex.
The fraction \frac{1}{2} can have many equivalent fractions. Equivalent fractions are fractions that represent the same value but have different numerators and denominators. Some examples of equivalent fractions for \frac{1}{2} are: • \frac{2}{4} • \frac{3}{6} • \frac{4}{8} • \frac{5}{10} • \frac{50}{100} These fractions are all equal to \frac{1}{2} because the ratio between the numerator and the denominator is the same.
To simplify the fraction ( \frac{857142}{999999} ), we can divide both the numerator and the denominator by their greatest common divisor (GCD), which is 142857. This gives us ( \frac{6}{7} ) in its simplest form. Therefore, ( \frac{857142}{999999} = \frac{6}{7} ).
:<math>{M}=\sqrt{\frac{2}{\gamma-1}\left[\left(\frac{q_c}{P}+1\right)^\frac{\gamma-1}{\gamma}-1\right]}</math>
The mathematical formula for calculating the square root of a number is x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}=x_n-\frac{x_n^2-S}{2x_n}=\frac{1}{2}\left(x_n+\frac{S}{x_n}\right).