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To find the sum of ( \frac{3}{4} ) and ( \frac{5}{16} ), first convert ( \frac{3}{4} ) to a fraction with a denominator of 16: ( \frac{3}{4} = \frac{12}{16} ). Now, add ( \frac{12}{16} ) and ( \frac{5}{16} ): ( \frac{12}{16} + \frac{5}{16} = \frac{17}{16} ). Therefore, the sum is ( \frac{17}{16} ) or ( 1 \frac{1}{16} ).
To multiply (7 \frac{1}{2}) by (1 \frac{1}{2}), first convert the mixed numbers to improper fractions. (7 \frac{1}{2} = \frac{15}{2}) and (1 \frac{1}{2} = \frac{3}{2}). Now, multiply the fractions: [ \frac{15}{2} \times \frac{3}{2} = \frac{45}{4}. ] Finally, convert (\frac{45}{4}) back to a mixed number, which is (11 \frac{1}{4}).
To calculate ( \frac{3}{5} \times \frac{3}{8} ), you multiply the numerators and the denominators: ( \frac{3 \times 3}{5 \times 8} = \frac{9}{40} ). Therefore, ( \frac{3}{5} \times \frac{3}{8} = \frac{9}{40} ).
Sure, here are two examples of complex fractions: **Example 1**: [ \frac{\frac{3}{4}}{\frac{5}{6}} ] This is a complex fraction where the numerator is (\frac{3}{4}) and the denominator is (\frac{5}{6}). **Example 2**: [ \frac{\frac{2x + 1}{3}}{\frac{7}{2x - 4}} ] This is a complex fraction where the numerator is (\frac{2x + 1}{3}) and the denominator is (\frac{7}{2x - 4}). In both examples, the fractions within the numerator and the denominator make the overall fraction complex.
To find the fraction of pizza that was uneaten, we first add the fractions eaten by each workman: ( \frac{1}{3} + \frac{1}{4} + \frac{1}{6} ). The least common multiple of 3, 4, and 6 is 12, so we convert the fractions: ( \frac{4}{12} + \frac{3}{12} + \frac{2}{12} = \frac{9}{12} ). Therefore, the fraction of pizza that was uneaten is ( 1 - \frac{9}{12} = \frac{3}{12} ), which simplifies to ( \frac{1}{4} ).