11/100
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If you mean: (0, 11) then y = x+11
011 & 009 Since no decimal point is given , then drop the prefix zeroes. Hence 11 & 9 . It follows that 11 > 9
Base2 011 = 11 Base3 011 = 10 Any base above that: Base2(11) equals 3
Divide the binary number into 3 bit segments starting from the right, then convert each 3 bit section into its decimal equivalent. 111 011 110 101 = 7 3 6 5 (111 = 7, 011 = 3, 110 = 6, and 101 = 5).
Convert each "digit" of the octal into a triplet of binary digits, according to the following rule: Octal Binary 0 000 1 001 2 010 3 011 4 100 5 101 6 110 7 111 So, for example, octal 53 = binary 101 011 [= decimal 43]