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Each increment in the Richter scale represents a ten-fold increase in the shaking magnitude of the earthquake.

In most countries, though, seismologists now use the moment magnitude scale. An increment of 1 on this scale represents a 101.5 fold increase in the energy released. 101.5 = sqrt(1000) = approx 32.

Q: What is difference in each 1 increment of earthquake?

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The difference between each number is decreasing by 1 each time. Therefore, the difference between the final number and the next number in the sequence will be 6. Therefore, 50 - 6 = 44.

The difference in place is 1/20.

Since their difference is zero, they're the same number.Since they're the same number, each one is 1/2 of 150.Both numbers are 75 .

A geometric sequence (aka Geometric Progression or GP) is one where each term is the previous term multiplied by a constant (the common difference) As division is the inverse of multiplication, each term can also be said to be the previous term divided by the reciprocal of the constant. The sum Sn of n terms of a GP can be found by: Sn = a(1 - rⁿ)/(1 - r) = a(rⁿ - 1)/(r - 1) where: a is the first term r is the common difference n is the number of terms If the value of the common difference is between -1 and 1 (ie |r| < 1), then the sum of the GP will be finite since as n→ ∞ so rⁿ → 0, and will be: S = a/(1 - r)

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INR increment the content of register/memory by 1and result is stored in same place. INX increment the register pair by 1(no flags are affected)

One millimetre more than previously.

There is no such increment operator in C language to increment the value of a variable by 2.An increment operator only increments the value by 1. however you can apply the increment operator twice to get an increment of 3. No: you cannot: ++(++a) won't compile. Yes. Example: a += 2; but += is not an increment operator, it's a shorthand of a=a+2; just like a++ is a shorthand for a= a+1

As written in the c programming language to find the LCM for up to 50 numbers. All that needs to be done is compile this. It is my first draft of the program, as it was due for a class 2 hrs ago, but if you wish to try and optimize it, that's your task. ----------------------------------------------------------------------------------------------------------- #include <stdio.h> #define NUMFACT 50 void FindFactor(int[]); int Min(int[]); int Max(int[]); int calc(int[]); int check(int[]); void bubbleSort(int[]); void Display(int[],int); int main() { int factors[NUMFACT] = {0}; //FACTORS ARRAY INITIALIZED WITH 0'S int lcf; //LOWEST COMMON FACTOR FindFactor(factors); lcf = calc(factors); bubbleSort(factors); Display(factors, lcf); return(0); } void FindFactor(int factors[]) { int tempvalue; //TEMP VALUE TO BE STORED IN FACTOR ARRAY int location = 0; //LOCATION IN VECTOR TO PLACE INPUT NUMBER do { printf("Enter factor: "); scanf("%d",&tempvalue); if (tempvalue != -1) { factors[location] = tempvalue; } ++location; } while (tempvalue != -1 && location <=49); } int Min(int factors[]) { int increment; //INCREMENT EACH PASS int min = Max(factors); //MAX VALUE IN FACTORS CHANGED TO LOWEST int location; //LOCATION OF THE MIN VALUE IN ARRAY for(increment = 0 ; increment < 49 ; increment++) { if (factors[increment] != 0) { if(factors[increment] < min) { min = factors[increment]; } } } for(increment = 0 ; increment < 49 ; increment++) { if(min 0); lcf = copyfactors[0]; return(lcf); } int check(int factors[]) { int increment; // INCREMENT EACH PASS int value = 1; //TRUE VALUE RETURNED IF IF-LOOP IS ALWAYS FALSE for(increment = 1 ; increment < 49 ; increment++) { if (factors[increment] != 0) { if (factors[increment-1] != factors[increment]) { value = 0; } } } return(value); } int Max(int factors[]) { int max = 0; //START VALUE SINCE # CAN'T BE LESS THAN 0 int increment; //INCREMENT EACH PASS for(increment = 0 ; increment < 50 ; increment++) { if (factors[increment] > max) { max = factors[increment]; } } return(max); } void bubbleSort(int factors[]) { int numPasses; //LCV THAT CONTROLS # OF PASSES int lcv; //LOOP CONTROL VARIABLE FOR SORTING int temp; //HOLDS VALUE DURING SWAP for(numPasses = 1; numPasses < NUMFACT ; numPasses++) { for(lcv = 0 ; lcv < NUMFACT - numPasses ; lcv++) { if(factors[lcv] > factors[lcv+1]) { temp = factors[lcv]; factors[lcv] = factors[lcv+1]; factors[lcv+1] = temp; } } } } void Display(int factors[],int lcf) { int increment; //INCREMENT EACH PASS printf("The factors of %d are:",lcf); for(increment = 0; increment < 50 ; increment++) { if(factors[increment] != 0) { printf(" %d",factors[increment]); } } printf("\n"); }

you++ will return the current value of you and increment it. ++you will increment it and then return the new value of you. So, for example: int you = 0; cout << you++; // this will print 0 cout << you; // this will print 1 int you = 0; cout << ++you; // this will print 1 cout << you; // this will also print 1

each memory increment is 1024 times the previous. 1 mb =1024 bytes and to answer the question 1gb = 1024 mb Hope this helps

Both the prefix and the postfix increment operators increment the operand. The difference is what is the value of the expression during the evaluation of the expression. In the prefix form, the value is already incremented. In the postfix form, it is not. int a = 1; int b = ++a; // both a and b are now equal to 2 int a = 1; int b = a++; // a is equal to 2 and b is equal to 1

increment operator increments the variable by 1 at a time and decrement operator decrements by 1 in this we have two types increments pre_increment and post increment. In pre_increment the original value is incremented by 1 and assign the new value n=10 i=++n then i =11 In post increment the original value is assigned and after it increments value by 1. n=10 i=n++ then i=10 example: k=5 i=k++ + ++k i=? ans: in first k++ value is 5 second ++k value is 7 i=5+7=12

The increment operator in C++ is defined by operator++(). All arithmetic types (char, int, float, double, long, short, long long and long double) and all pointer types except void* are supported by operator++(). User-defined types can overload operator++() to provide support where required. operator++() has two versions, prefix increment and postfix increment. Prefix increment behaves as one would expect, incrementing the operand by 1 and returning the modified value. Postfix increment also increments the operand, however, the return value is the pre-incremented value. To understand the difference between prefix and postfix, consider the following: int i = 0; int j = ++i; // i=1, j=1 int i = 0; int j = i++; // i=1, j=0

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The Richter scale measures the magnitude of an earthquake, not its intensity. The Richter scale ranges from 1 to 10, with each whole number increase representing a tenfold increase in amplitude of seismic waves. Each level on the scale corresponds to an increase in energy released by the earthquake.