If 16 - 7d = -3 d + 2, collecting like terms with "d" on the left side yields -4d = -14, or d = 14/4 = 7/2.
-60 - 17 + (4-1)d + (10-2)c = -77 + 3d + 8c.
C squared times the square root of 5cd over 2 times d to the third power
d = 2
It is: 1-3(-4)+4(-2) = 5
2s: 2 electrons 5p: 6 4f: 14 3d: 10 4d: 10
They are: 6d+6 or 6(d+1)
2-4d = -2
Drawing 5D is impossible cause that's the twilight zone, 4D has 2 do with textures (touching) and smell, 3D wuld b like a cube, 2D is simple flat shapes like a square and 1D is just lines.
The electron configuration of Zr is [Kr] 4d2 5s2. This means that Zirconium has a total of 40 electrons distributed in the 4d and 5s orbitals around the nucleus.
It is: 2(4d) = 8d
4d-2 equals 6b-4
In the electron configuration of tin (Sn), the 3d electrons are not present. Tin has a configuration of [Kr] 5s2 4d10 5p2, which means it has 2 electrons in the 5s orbital, 10 electrons in the 4d orbital, and 2 electrons in the 5p orbital.
1D is the fastest time at the jackpot. The 2D would be typically 1/2 second slower, and 3D is a 1/2 second slower than that. Usually the jackpot will advertise "1/2 second splits" or "1/2, 1/2, 1" (for a 4D). Example: 5D barrel race (1/2 second splits) 1D - 15.513 2D - 16.013 3D - 16.513 4D - 17.013 5D - 17.513 4D barrel race (1/2, 1/2, 1 second split) 1D 15.513 2D 16.013 3D 16.513 4D 17.513 I think this is right.
If 16 - 7d = -3 d + 2, collecting like terms with "d" on the left side yields -4d = -14, or d = 14/4 = 7/2.
1s-2s-2p-3s-3p-3d-4s-4p-4d-4f-5s-5p-5d-5f-6s-6p-6d-7s
-60 - 17 + (4-1)d + (10-2)c = -77 + 3d + 8c.