If y = sin(cos(tan(x)))
Using the chain rule: (f(g(x)))' = f'(g(x)).g'(x)
Then dy/dx = cos(cos(tan(x))).-sin(tan(x)).sec2(x)
= -cos(cos(tan(x))).sin(tan(x)).sec2(x)
Unfortunately I don't think this can be simplified much more.
( sec = 1/cos )
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