Y=X^2 is a function for it forms a parabola on a graph.
the graph is moved down 6 units
The graph is a parabola facing (opening) upwards with the vertex at the origin.
Assuming you meant y=x2 & y=x2-4 They are both straight-line graphs, however - they produce different results. Using the values of 1,2,3,4 & 5 for x (as an example)... In the first equation, the value of y would be 1,4,8,16 & 25 In the second equation, y would be -3,0,4,12 & 21
One. It is a double root.
Y=X^2 is a function for it forms a parabola on a graph.
No translation will invert a quadratic graph.
the graph is moved down 6 units
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
9
You may mean, what is the graph of the function y = x^2 + 3. This graph shows a upward parabola with a y-intercept of 3 and a minimum at x=0.
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
The graph is a parabola facing (opening) upwards with the vertex at the origin.
Yes. Think of y as being a function of x. y = f(x) = x2 + 1
y = x2 + 4 The graph is a parabola, with its nose at y=4 on the y-axis, and opening upward.
Assuming you meant y=x2 & y=x2-4 They are both straight-line graphs, however - they produce different results. Using the values of 1,2,3,4 & 5 for x (as an example)... In the first equation, the value of y would be 1,4,8,16 & 25 In the second equation, y would be -3,0,4,12 & 21
One. It is a double root.