The algebraic expression for twice a number ( k ) plus the quantity ( s - 2 ) can be written as ( 2k + (s - 2) ). This combines the two components by first calculating twice the value of ( k ) and then adding the result to ( s - 2 ). Therefore, the complete expression is ( 2k + s - 2 ).
(9 - y)(a + 5)
6n - (2n + 10 - 5)
The statement "Twice the quantity of a number plus two is greater than the number plus five" can be expressed mathematically as (2x + 2 > x + 5), where (x) is the number. To solve this inequality, we can subtract (x) from both sides, resulting in (x + 2 > 5). Further simplifying gives (x > 3). Thus, the solution indicates that the number must be greater than 3.
2y+8?
The algebraic expression for twice a number ( k ) plus the quantity ( s - 2 ) can be written as ( 2k + (s - 2) ). This combines the two components by first calculating twice the value of ( k ) and then adding the result to ( s - 2 ). Therefore, the complete expression is ( 2k + s - 2 ).
2x + 2 > x + 5
n>3 2x + 2 > x + 5
irdk
A plus number.
(9 - y)(a + 5)
6n - (2n + 10 - 5)
The statement "Twice the quantity of a number plus two is greater than the number plus five" can be expressed mathematically as (2x + 2 > x + 5), where (x) is the number. To solve this inequality, we can subtract (x) from both sides, resulting in (x + 2 > 5). Further simplifying gives (x > 3). Thus, the solution indicates that the number must be greater than 3.
a minus and a plus equal a minus number yeh dude
No, it becomes a plus, since minus x minus = plus
2y+8?
x = 3.5