The balanced equation for the reaction between aluminum and hydrochloric acid is: 2Al + 6HCl -> 2AlCl3 + 3H2
2Al + 6HCl >> 2AlCl3 + 3H2
2Al + 6HCl --> 2AlCl3 + 3H2
The balanced equation for hydrochloric acid reacting with aluminum metal is: 2Al(s) + 6HCl(aq) → 2AlCl3(aq) + 3H2(g).
The reaction is 2Al+ 6HCl --> 2AlCl3 + 3H2
The chemical equation for this reaction is: 2Al(s) + 6HCl(aq) -> 2AlCl3(aq) + 3H2(g)
2Al(s) + 6HCl(aq) ----- 2AlCl3(aq) + 3H2(g).
Al2O3 + 6HCl >> 2AlCl3 + 3H2O
2AlBr3(aq) + 3Cl2(g) = 2AlCl3(aq) + 3Br2(l)
The reaction between aluminum (Al) and hydrochloric acid (HCl) produces aluminum chloride (AlCl3) and hydrogen gas (H2). The balanced chemical equation for this reaction is: 2Al + 6HCl → 2AlCl3 + 3H2
6HCl + Al2(CO3)3 ==> 2AlCl3 + 3CO2 + 3H2O
To determine the limiting reactant, we need to calculate the amount of each reactant in terms of the same unit (moles). Then, we compare the mole ratio of the reactants from the balanced chemical equation. In this case, convert 60.0 grams of aluminum to moles and 25 grams of hydrochloric acid to moles. Compare the moles of each reactant to determine the limiting reactant.