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How do you solve m²-n²196?
I'm assuming you meant m2-n2+196 m2-n2=-196 m2=-196+n2 m=14i+n n=m-14i
How many sq ft in a 30m2?
From "Fluid Mechanics" by Streeter & Wylie (c) 1979 .3048m = 1 ft so... .3048 squared meters squared = 1 squared ft squared or... .0929 meters squared = 1 ft squared or... 1 ft squared /.0929 meters squared = 10.7639 ft squared/ meters squared so... 30 m2 times 10.7639 ft2/m2 = 322.9173 meters squared Answer: 322.9173 meters squared
How much is 500 meters squared in inches squared?
500 m2 = 775,001.55 inches squared.
What is 150 feet squared in meters squared?
Just over 13.9 m2
The product of 5 and a number squared?
5*n2
What is square root of m2-n2?
The square root of m2 - n2 cannot be simplified.
How do you solve m²-n²196?
I'm assuming you meant m2-n2+196 m2-n2=-196 m2=-196+n2 m=14i+n n=m-14i
What is the answer to m2-8m equals -16?
if by m2 you mean m multiplied by 2, then m= 2 2/3if by m2 you mean m squared, then m still =2 2/3, because the m squared becomes m times m which equals 2m
What is the answer to mn5-m3n by factoring polynomial?
mn(n4-m2)mn(n2+m)(n2-m)
How many sq ft in a 30m2?
From "Fluid Mechanics" by Streeter & Wylie (c) 1979 .3048m = 1 ft so... .3048 squared meters squared = 1 squared ft squared or... .0929 meters squared = 1 ft squared or... 1 ft squared /.0929 meters squared = 10.7639 ft squared/ meters squared so... 30 m2 times 10.7639 ft2/m2 = 322.9173 meters squared Answer: 322.9173 meters squared
How many meters squared are in a 24cm squared?
24 cm squared = 24 cm * 24 cm = 576 cm2 = 576/10000 m2 or 0.0576 m2
What Is the 3 times the difference of a number squared and 82?
Let n be the number. Then it's 3(n2 - 82).
How much is 500 meters squared in inches squared?
500 m2 = 775,001.55 inches squared.
What is 5980 meters squared in squared feet?
5980 m2 = 64,368.18 ft2
What is 150 feet squared in meters squared?
Just over 13.9 m2
How many meters squared are in a centimeter squared?
1 cm2 = 0.0001 m2
Are there infinitely many primes of the form n2-1 and n2-2 and n2-3 and n2-4?
n2-1 and n2-4 are trivial cases because of n2-m2=(n-m)(n+m). So the only prime of the form n2-1 is 3 and of the form n2-4 is 5.
