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What does m equals in mn equals m plus n?
m = n/(n-1)
Is m plus n equals n plus m the property of commutative?
no
Is m plus n equals n plus m commutative?
Yes.
What is the substition for m plus n equals 1000 0.05m plus 0.06n equals 57?
m + n = 10000.05m + 0.06n = 57
How do you solve for m plus n equals 1000 and 0.05m plus 0.06n equals 57?
Solve be substitution... m+n=1000 0.05m+0.06n=57 Take one of the equation and find "m" m=1000-n substitute into the other equation 0.05(1000-n)+0.06n=57 50-0.05n+0.06n=57 50-0.01n=57 -0.01n=-7 n=700 Now you have found "n" now find "m" m=1000-n m=1000-700 m=300 m=300 and n=700
What does m equals in mn equals m plus n?
m = n/(n-1)
Is m plus n equals n plus m the property of commutative?
no
Is m plus n equals n plus m commutative?
Yes.
What is the substition for m plus n equals 1000 0.05m plus 0.06n equals 57?
m + n = 10000.05m + 0.06n = 57
How do you solve L equals 2M plus 2N for N?
N=l-m
How do you make x the subject of m equals n plus (x over p)?
If: m = n+x/p then x = p(m-n)
M plus n equals 1000 0.05m plus 0.06n equals 57?
87
Clara wrote 2 expressions 1 n equals 1 plus n 2 n equals 2 plus N?
2 plus n is the true one, but 1 plus n is not?
N plus 7 equals 15 then what does n equals?
n = 8
Make x the subject of the formula y equals xsquared plus 2mx plus n?
y = x2 + 2mx + n complete the square y + m2 = x2 + 2mx + m2 + n = (x + m)2 + n (x + m)2 = y + m2 - n x + m = √(y + m2 - n) x = -m + √(y + m2 - n)
How do you solve for m plus n equals 1000 and 0.05m plus 0.06n equals 57?
Solve be substitution... m+n=1000 0.05m+0.06n=57 Take one of the equation and find "m" m=1000-n substitute into the other equation 0.05(1000-n)+0.06n=57 50-0.05n+0.06n=57 50-0.01n=57 -0.01n=-7 n=700 Now you have found "n" now find "m" m=1000-n m=1000-700 m=300 m=300 and n=700
If you have n plus 12 bracketed squared equals 161 plus M squared where n and m are integers and eg n equals 3 m equals 8 is there a method other than direct factorization to solve for n and m?
This is a hyperbola. It is best approached using Fermat's factorisation method. Seefermat-s-factorization-methodor google wikepedia. I don't know of any faster approach.
