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This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution.
Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water.
90 grams + 10 grams = 100 grams (mass of total solution).
(10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
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50 percent dextrose solution and you need a 1 percent dextrose soultion. How do you figure that out?
If the percents given are by weight or mass, this is very straightforward: The ratio between the desired percentage and the initial percentage is 1/50. Therefore, a given mass of initial solution must be diluted to 50 times its original mass to obtain the desired lower concentration, or in other words, 49 parts of diluent must be mixed with each part of initial solution. If the percents involve volume measurements, it would be necessary to take into account and change in density occasioned by the dilution.
How many parts per million of a solute is present in a solution that is 3 percent by mass?
30,000ppm
How do you find the mass percent mole fraction molality and molarity of a solution?
Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)
Convert 60 percent solution to 40 percent solution?
All percentages are in mass% and all quantities are in grams (mass), be sure do not to take volumes into account because mass is 'additive', volumes are not quantitatively additable!Answer: Take whatever mass of 60 percent solution you have, multiply that mass by 20 (=60-40) and then divide that amount by 40, this is how much water to add to get an 40% solution.Example: Suppose you have 100 gram of 60% solution, then you should add:100 * (60-40)/40 = 100*0.50 = 50 gram of water; this is to be added to 100 gram of 60% solution to get (50 + 100 =) 150 gram of 40% solution.(see on top of the page to know why this calculation method is not valid for 'volumes')
A 5.0 percent glucose solution has a specific gravity of 1.06. What is the mass in g of 335.7 mL of the glucose solution?
335.7*1.06 = 355.842 grammes
