Put them in numerical order and ther median is the one in the middle
Answer: 20
In the example provided, the quartiles are: 25% = 16.5 (the median of {15, 16, 17, 18}) 50% = 18.5 (the median of {15, 16, 17, 18, 19, 20, 21, 22}) 75% = 20.5 (the median of (19, 20, 21, 22})
16.5 is the median.
Order them: 15 16 17 21 21 Find the middle one: 17 That is the median
The mean is 21 and 1/3 The median is 22 The mode is 24
It is 18, the middle number when they are in order.
In the example provided, the quartiles are: 25% = 16.5 (the median of {15, 16, 17, 18}) 50% = 18.5 (the median of {15, 16, 17, 18, 19, 20, 21, 22}) 75% = 20.5 (the median of (19, 20, 21, 22})
16.5 is the median.
Mean: 19 and 1/6 Median: 20 There is no mode.
The numbers are 15 21 21 24 25 26 35.
Order them: 15 16 17 21 21 Find the middle one: 17 That is the median
The mean is 21 and 1/3 The median is 22 The mode is 24
It is 18, the middle number when they are in order.
Mean = 21.6 Median = 19.5 Mode = 20 and 21 ------------------------------------------------------------------------ If the "2 1" (between 18 and 20 at the end) is supposed to be "21" then Mean = 26 Median = 20 Mode = 20
In order, the numbers are 18, 21, 24 and 37. Since there are an even number (4) of them, the median is the average of the middle two. ie median = (21+24)/2 = 22.5
23
To find the median of the numbers 12, 13, 14, 15, 16, 17, 18, 19, 20, and 21, first, arrange them in order (they are already sorted). Since there are 10 numbers (an even count), the median is the average of the two middle numbers, which are 16 and 17. The median is therefore (16 + 17) / 2 = 16.5.
15, 15, 20, 24, 25, 25, 30 Mode: 22 Median: 24