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Money deposited P: 5000 Rate of Interest r: 6 no. of years n: 1 Interest I = p * n * r / 100 = 300 Total money at the end of one year = P + I = 5300
15 amounts of money. The formula for finding how many combinations is: n to the 2nd power -1 In this case n = 4 (because 4 is how many objects you have) So to calculate this you do: 4(4)- 1 16-1 15
.25n + .5n + 18 = n.75n - n = -18-.25n = -18.25n = 18n = 72
Also, I have to use the formula: Use the compound interest formula A = P (1 + i)n, where A is the accumulated amount, P is the principal, i is the interest rate per year, and n is the number of years.
n+n-n-n-n+n-n-n squared to the 934892547857284579275348975297384579th power times 567896578239657824623786587346378 minus 36757544.545278789789375894789572356757583775389=n solve for n! the answer is 42