12 cm3 of Mercury is more dense than 7 cm3 of Hydrogen (at the same Temperature and Pressure), so 12 cm3 is more dense than 7 cm3.
Whereas 12 cm3 of Hydrogen is less dense than 7 cm3 of Mercury (at the same temperature and pressure), so 7 cm3 is more dense than 12 cm3!
Density depends upon the mass of the substance contained in the volume, so given two volumes, no statement can be made about the relative densities of those volumes without any knowledge of the mass of the volumes: density = mass/volume.
Knowing the densities of the substances of the volumes, the volume is immaterial as the density is the same - density is the mass per unit volume.
7*12*6 = 504 cm3
A cylinder with a radius of 7 centimeter and a height of 12 centimeter has a volume of 1,847.26 cm3.
17
density = mass/volume In your example, density(object) = 5.5/7 g/cm3 = 0.8 g/cm3. Note that I rounded the last number to one significant decimal, as the volume (7 cm3) is specified with only one significant decimal. A volume of 7 cm3 varies between 6.5 cm3 and 7.4 cm3, and the answer conforms to a "good estimate". If the volume had been specified as 7.0 cm3, then the answer would be different, namely density(object) = 5.5/7.0 g/cm3 = 0.79 g/cm3, rounded to two significant decimals, as we now have assumed more accuracy, the answer is also a "better estimate", because in the first case, the answer would actually range between 5.54/6.50 = 0.852 and 5.45/7.49 = 0.728 (which average to exactly 0.79, please check this). <Feb 18, 2014 - B.C.>
The fraction 7/12 cannot be reduced any more.
7*12*6 = 504 cm3
A cylinder with a radius of 7 centimeter and a height of 12 centimeter has a volume of 1,847.26 cm3.
The density is calculated by dividing the mass of an object by its volume. In this case, the density is 11.29 g/cm3 (79 g รท 7 cm3 = 11.29 g/cm3).
17
The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7
5*6*7 = 210 cm35*6*7 = 210 cm35*6*7 = 210 cm35*6*7 = 210 cm3
12 hundredths would be .12 and seven tenths would be .7So, 12 hundredths, is NOT more than 7 tenths.12 hundredths is less than 7 tenths.
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density = mass/volume In your example, density(object) = 5.5/7 g/cm3 = 0.8 g/cm3. Note that I rounded the last number to one significant decimal, as the volume (7 cm3) is specified with only one significant decimal. A volume of 7 cm3 varies between 6.5 cm3 and 7.4 cm3, and the answer conforms to a "good estimate". If the volume had been specified as 7.0 cm3, then the answer would be different, namely density(object) = 5.5/7.0 g/cm3 = 0.79 g/cm3, rounded to two significant decimals, as we now have assumed more accuracy, the answer is also a "better estimate", because in the first case, the answer would actually range between 5.54/6.50 = 0.852 and 5.45/7.49 = 0.728 (which average to exactly 0.79, please check this). <Feb 18, 2014 - B.C.>
To find the density of copper and tin, we need to calculate the mass and volume of each metal in both alloys. Once we have those values, we can then determine the density by dividing the mass by the volume. For the first alloy with 8 cm3 of copper, we find the density of copper to be 9.5 g/cm3 and for tin, it is 7.75 g/cm3. Similarly, for the second alloy with 9 cm3 of copper, the density of copper is 17.56 g/cm3, and for tin, it is 14.36 g/cm3.
The fraction 7/12 cannot be reduced any more.
7 and 12, 12 is 5 more than 7 and 7+12 is equal to or ='s 19.