66
33
The sequence appears to be decreasing with varying intervals: 50 to 33 (17), 33 to 25 (8), 25 to 20 (5), 20 to 17 (3), 17 to 14 (3), 14 to 13 (1), and 13 to 11 (2). The differences between the numbers suggest that the next number decreases by 1 from 11, resulting in 10. Therefore, the next number in the sequence is 10.
2/3*33 =2/11 =.1818181818181818 with 18 repeating.
22 12+2x = 33 2x = 33-22 = 11
The given sequence is 1, 6, 13, 22, 33. To find the nth term, we can observe that the differences between consecutive terms are 5, 7, 9, and 11, which indicates that the sequence is quadratic. The nth term can be expressed as ( a_n = n^2 + n ), where ( a_n ) is the nth term of the sequence. Thus, the formula for the nth term is ( a_n = n^2 + n ).
4 11 11 22 22 26 33 33. =22
One possibility: -3
The counting sequence is making increments of 11,that is, the n-th term will = 11 x nn = 12,t = 12 x 11= 132
2×11 -33 22-33 -11 1 11---1
The factors of 22 are: 1, 2, 11, 22. The factors of 33 are: 1, 3, 11, 33.
11. 11 x 2 = 22 11 x 3 = 33
The least common multiple of 11 , 22 , 33 = 66
The GCF is 11.
The greatest factors of any positive integers are the integers themselves. The GCF of 22 and 33 is 11.
33
The sequence appears to be decreasing with varying intervals: 50 to 33 (17), 33 to 25 (8), 25 to 20 (5), 20 to 17 (3), 17 to 14 (3), 14 to 13 (1), and 13 to 11 (2). The differences between the numbers suggest that the next number decreases by 1 from 11, resulting in 10. Therefore, the next number in the sequence is 10.
33