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745 x (1 - (1/10)) = 745 - 74.5 = 670.5
21 goes into 136 six times. This can be calculated by dividing 136 by 21, which equals 6 with a remainder of 10. Since we are looking for the whole number of times 21 goes into 136, we ignore the remainder.
The number 136 in binary is the eight-digit number 10001000. The digits in a binary number are exponents of 2 rather than 10, so that for an eight-digit number in binary, the digit places represent 128, 64, 32, 16, 8, 4, 2, 1 instead of increasing values of 10. 10001000 = 128 + (0x64) + (0x32) +(0x16) + 8 + (0x4) + (0x2) + (0x1) = 136
The number 136 in binary is the eight-digit number 10001000. The digits in a binary number are exponents of 2 rather than 10, so that for an eight-digit number in binary, the digit places represent 128, 64, 32, 16, 8, 4, 2, 1 instead of increasing values of 10. 10001000 = 128 + (0x64) + (0x32) +(0x16) + 8 + (0x4) + (0x2) + (0x1) = 136
7.45 x 10 ^2