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No, it is a linear transformation.
The correlation remains the same.
For a N(0, 1) distribution, no linear transformation is necessary and so the z-score is the value of the coordinate on the horizontal axis.For a N(0, 1) distribution, no linear transformation is necessary and so the z-score is the value of the coordinate on the horizontal axis.For a N(0, 1) distribution, no linear transformation is necessary and so the z-score is the value of the coordinate on the horizontal axis.For a N(0, 1) distribution, no linear transformation is necessary and so the z-score is the value of the coordinate on the horizontal axis.
If a linear transformation acts on a vector and the result is only a change in the vector's magnitude, not direction, that vector is called an eigenvector of that particular linear transformation, and the magnitude that the vector is changed by is called an eigenvalue of that eigenvector.Formulaically, this statement is expressed as Av=kv, where A is the linear transformation, vis the eigenvector, and k is the eigenvalue. Keep in mind that A is usually a matrix and k is a scalar multiple that must exist in the field of which is over the vector space in question.
I t is a form of transformation in which all the linear dimensions of a shape are increased by the same proportion.