That is the equation, or would be if the signs were shown. The factors are (x - 11)(x + 4) which is equivalent to x2 - 7x - 44 or (x + 11)(x - 4) which is equivalent to x2 + 7x - 44.
x2-7x-44 = (x+4)(x-11) when factored
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
x2+7x-8 = (x-1(x+8)
Restate the question: Factor the polynomial x2 + 7x + 10. You look for two numbers which multiply to make 10 and add to make 7. They are 5 and 2. Now put them into the two factors: (x + 5)(x + 2). Check your factors by multiplying using 'FOIL': x2 + 2x + 5x + 10 = x2 + 7x + 10. Check!
That is the equation, or would be if the signs were shown. The factors are (x - 11)(x + 4) which is equivalent to x2 - 7x - 44 or (x + 11)(x - 4) which is equivalent to x2 + 7x - 44.
x2-7x-44 = (x+4)(x-11) when factored
(x + 11)(x - 4)
x2-7x-44 = (x+4)(x-11) when factored
Step 1: 3(x2 + 7x - 44) Step 2: 3(x + 11)(x - 4)
x2 × 7x = 7x3
x^2 + 7x -18 = (x - 2)(x + 9)
x - 11 Apex - Algebra II
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
x2+7x+12
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
x2+7x-8 = (x-1(x+8)