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What is the perimeter of a square 324 into inches?
If the area of the square is 324 square inches then its perimeter is 4*18 = 72 inches
What is the perimeter of a square with are of 324?
72
How do you get the answer for what is the perimeter of a square with area 324?
you divide the area by four and now you can find the perimeter
What is the area and perimeter of a square with sides 18 inches?
Area of square: 324 square inches Perimeter of square: 72 inches
What is the perimeter of a square plot that is 81m?
324 meters if 81 m is a side length 36 meters if 81 m is the area
What is the perimeter of a square 324 into inches?
If the area of the square is 324 square inches then its perimeter is 4*18 = 72 inches
What is the perimeter of a square with are of 324?
72
How do you find the perimeter of a square with area of 324?
The square root of 324 is 18 and 4*18 = 72 units of measurement which is the perimeter of the square.
Perimeter of a square with area of 324?
72 because if the area is 324 and you make a block chart and count the sides it will equal 72
How do you get the answer for what is the perimeter of a square with area 324?
you divide the area by four and now you can find the perimeter
What is the perimeter of a square with area of 324?
72
What is the perimeter of a square with an area of 324?
72 units
Perimeter of a square is 72 in what is the area?
The area is 324 square units.
The perimeter of a square is 72 in. what it's area?
The area is 324 square inches.
What is the area and perimeter of a square with sides 18 inches?
Area of square: 324 square inches Perimeter of square: 72 inches
How do you solve a perimeter of a square with an area of 324cm?
The square root of 324 is 18 so the perimeter must be 4*18 = 72 cm
How do you find perimeter of a square with area of 324?
Say one of the sides is s. Because it is a square, both the length and width (both sides) are s. Area = length x width So 324 = s x s, or 324 = s2. So s is equal to the square root of 324. Because perimeter is the sum of the sides, add s + s + s + s.
