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The equation of a line that is perpendicular to 3y = -x + 9 and that has a y intercept of 6 is y = 3x + 6.
The slope of the first line is -1/3, from the slope-intercept form y = mx + b, or y = -x/3 + 3. The perpendicular slope is 3, by negating and inverting -1/3. Add the intercept to the slope-intercept form and you get y = 3x + 6.
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Earn +20 ptsQ: What is perpendicular to y equals -8x plus 6?
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