The equation of a line that is perpendicular to 3y = -x + 9 and that has a y intercept of 6 is y = 3x + 6.
The slope of the first line is -1/3, from the slope-intercept form y = mx + b, or y = -x/3 + 3. The perpendicular slope is 3, by negating and inverting -1/3. Add the intercept to the slope-intercept form and you get y = 3x + 6.
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X equals 9.
basic algebra -8x + 6 = -58 -8x = -64 x = (-64/-8) x = 8
9x + 3x - 9x = 6 + 8x - 113x = 8x - 11-5x = -11x = 2.2 or 11/5