Best Answer

The equation of a line that is perpendicular to 3y = -x + 9 and that has a y intercept of 6 is y = 3x + 6.

The slope of the first line is -1/3, from the slope-intercept form y = mx + b, or y = -x/3 + 3. The perpendicular slope is 3, by negating and inverting -1/3. Add the intercept to the slope-intercept form and you get y = 3x + 6.

Q: What is perpendicular to y equals -8x plus 6?

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(1, 1)

DIE

X equals 9.

basic algebra -8x + 6 = -58 -8x = -64 x = (-64/-8) x = 8

9x + 3x - 9x = 6 + 8x - 113x = 8x - 11-5x = -11x = 2.2 or 11/5

Related questions

+ 1/8

8x-7 plus 2x equals 6 plus 5x plus 2?

(1, 1)

11x = 8x-6.............. 11x-8x = -6................... 3x= -6 x = -2

55

DIE

X equals 9.

-8x + 6 = -58 -8x = -64 x= -64/-8 x = 8

-2

basic algebra -8x + 6 = -58 -8x = -64 x = (-64/-8) x = 8

9x + 3x - 9x = 6 + 8x - 113x = 8x - 11-5x = -11x = 2.2 or 11/5

5x+1+x-2 = 8x+6 5x+x-8x = 6+2-1 -2x = 7 x = -3.5