There is a 4 in 6 (or 2 in 3) probability of rolling a number less than a five on a standard number cube.
Any normal die contains three numbers that are less than 4 so the answer must be 1.
Assuming the 5 cubes are standard, unbiased dice with the numbers 1-6 on the faces: There are 4 numbers {1, 2, 3, 4} which are less than 5. Each has a probability of 1/6 of appearing on 1 die, thus each die has a probability of 4 × 1/6 = 4/6 = 2/3 of showing a number less than 5 → probability of all 5 dice showing a number less than five = (2/3)⁵ = 32/243 ≈ 0.132 = 13.2 %
1 out of 2
1/12
The probability is zero. No number can be less than 3 and greater than 4.
The probability of rolling a number less than 5; which is a 4, 3, 2, or 1 is 4/6 or 2/3. The probability of tossing a head is 1/2. So, the probability of a roll less than 5 and a head is 2/3*1/2 or 1/3 or 0.333. 4/12
The probability of getting a particular suit (hearts, spades, diamonds, clubs) is 1 in 4. The probability of getting a card less than 8 (2, 3, 4, 5, 6, 7) is 6 in 13. The probability, then, of getting a particular suit less than 8 is (1 in 4) times (6 in 13) or 6 in 52 or 3 in 26.
Assuming you're using 6-sided dice, The probability of rolling less than 4 on one die is 1/2. To roll 3 dice and get less than 4 on 2 (and only 2) of them is 3/8.
Counting Ace as less than 6, then there are 20 cards out of 52 less than 6, for a probability 5/13. Counting Ace as high with 2 being the lowest card, there are 16 cards less than 6 for a probability of 4/13.
It is not clear whether the question is for "less than 4" or "greater than 4".
It depends on the pie chart. It may not have any numbers less than 4, or all of them.
There is a 4 in 6 (or 2 in 3) probability of rolling a number less than a five on a standard number cube.
Total numbers on the cube = 6 Numbers less than 5 = 4 Probability = 4/6 = 2/3 = 662/3 %
Any normal die contains three numbers that are less than 4 so the answer must be 1.
Assuming the 5 cubes are standard, unbiased dice with the numbers 1-6 on the faces: There are 4 numbers {1, 2, 3, 4} which are less than 5. Each has a probability of 1/6 of appearing on 1 die, thus each die has a probability of 4 × 1/6 = 4/6 = 2/3 of showing a number less than 5 → probability of all 5 dice showing a number less than five = (2/3)⁵ = 32/243 ≈ 0.132 = 13.2 %
It is 3/36 = 1/12