Restate the question: "What is the value of radical (-12)?"
If this is not your question, please clarify and resubmit the question. :-)
If we are dealing with real numbers, then there is no answer: there is no real number whose square is a negative number.
If you are in the realm of imaginary and complex numbers, then you can say that:
rad(-12) = rad(-1*12) = rad(-1)*rad12 = i*rad12, where i is the number whose square is -1.
rad12 in turn can be written as rad(4*3) = 2rad3 =~ 3.5
The final answer can be written as 2irad3 or ~3.5i.
You don't. If the negative sign is outside the radical, then you take the square root of the number and apply the negative. If the negative sign is inside the radical, you will have an imaginary number.
maby.... maby not...
It depends what power is associated with the radical.
(-169).5 = 13i
Technically,no. A radical equation has a radical (Square root) in it, and has two solutions because the square root can be positive or negative.
You cannot factor negative radical numbers because the square of a number must always be positive. A negative number multiplied by a negative number produces a positive number. So, it is impossible to have a negative radical.
easy, lets take radical negative 3 for example. you can take out a "i" because i = the radical negative one. There fore the answer is i radical 3.
Tin ions are positive (cations).
2i radical 5 * * * * * No. it is ± i*radical(25) which is ± 5i. Not sure why the answer is requireed in radical form.
You don't. If the negative sign is outside the radical, then you take the square root of the number and apply the negative. If the negative sign is inside the radical, you will have an imaginary number.
12 radical 6 x 6 radical 6 = 72 x 6 = 432
maby.... maby not...
12 radical 2
It depends what power is associated with the radical.
(-169).5 = 13i
12 radical 2 you multiply 6 and 2 :)
Technically,no. A radical equation has a radical (Square root) in it, and has two solutions because the square root can be positive or negative.