Guramr Cube
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The probability cannot be 625 since, by definition, it must be a number in the range [0, 1].
This is kind of neat. I drew a three dimensional cube. Then divided the faces into 16 squares per face. Then started counting which of those little cubes would have a painted face. I get: 1 red face - 24 cubes 2 red faces - 24 cubes 3 red faces - 8 cubes 4, 5, & 6 red faces - 0 cubes
There would be 8 will 3 faces painted red, 24 with 2 faces painted red, 24 with 1 face painted red, and 8 that have no faces painted red.
Six. Red1 + Blue6, R2+B5, R3+B4, R4+B3, R5+B2 and R6+B1,
volume is to a cube volume is to a cube