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instantaneous acceleration

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No it does not.

The graph is a distance-time graph so the coordinates of a point on the graph represent the position (distance) at the specified time. The gradient of the tangent to the curve at that point represents the instantaneous radial velocity. The second derivative at that point, if it exists, would represent the acceleration.

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Q: What is represented by a single point on a curved line in a distance time graph showing accelerated motion?
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