If you are looking for the angle between a line and another, then it is usually represented by Ө (theta). If you're looking for the gradient of a line, use m = rise/run or m = y2 - y1 / x2 - x1 , where m is the gradient, (x1,y1) and (x2,y2) are two fixed points on the cartesian plane.
x2 + x2 + x2 = (1 + 1 + 1)x2 = 3x2
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
x2 - 4
x2 - (2x)2 = x2 - 4x2 = -3x2 x2 - 2x2 = -x2
The base area is 15 + (x + 2)/x2.
The component form of a vector AB would typically be represented as (x2 - x1, y2 - y1), where A is at the point (x1, y1) and B is at the point (x2, y2).
If you are looking for the angle between a line and another, then it is usually represented by Ө (theta). If you're looking for the gradient of a line, use m = rise/run or m = y2 - y1 / x2 - x1 , where m is the gradient, (x1,y1) and (x2,y2) are two fixed points on the cartesian plane.
Line of symmetry: x = 3
x2 + x2 + x2 = (1 + 1 + 1)x2 = 3x2
The GCF is x2.
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x2 + x2 = 2x2
Vector magnitude is represented by the square root of the sum of the squares of the independent vector comonents; |V| = (x2 + y2 + z2)1/2.
x2 + x2 = 2x2
The answer would be 3x if 'X2' is '2x', but if 'X2' is x2, then the total answer would be x2 + x.
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2