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You look for the largest perfect square, and take it out. In this case: root(125) = root(25 x 5) = root(25) x root(5) = 5 x root(5).
0.5
Square root 5: ± 2.236068Square root 9: ± 3
3 square root of 5 cannot be rationalised.3 square root of 5 cannot be rationalised.3 square root of 5 cannot be rationalised.3 square root of 5 cannot be rationalised.
root(x+5)-root(x-5)=2 root(x+5)=2-root(x-5) x+5=4-4root(x-5)+x-5 4root(x-5)+6=0 root(x-5)=-3/2 x-5=9/4 x=9/4 +5 x=29/4
You look for the largest perfect square, and take it out. In this case: root(125) = root(25 x 5) = root(25) x root(5) = 5 x root(5).
Negative fourth root of a number= 1/the fourth root of the number. Fourth root of 625= 5 (5*5*5*5) 1/5
You can get a decimal approximation with a calculator, with Excel, etc. But if you want to keep it as a square root, the "standard form" is considered to be one that has no square roots in the denominator. In this case, to get rid of the square root in the denominator, you multiply both numerator and denominator by the square root of 5, with the following result: 3 / root(5) = 3 root(5) / root(5) x root(5) = 3 root(5) / 5 That is, three times the square root of 5, divided by 5.
The cube root of 125 is 5 -- that is 5*5*5 = 125
0.5
zero
5
Square root of 5 = ± 2.236068Square root of 11 = ± 3.316625
The square root of 15 times the square root of 5 can be simplified as the square root of (15 * 5), which equals the square root of 75. The square root of 75 can be further simplified as 5 times the square root of 3. Therefore, the square root of 15 times the square root of 5 is equivalent to 5 times the square root of 3.
Call this number "x". In this case:x = root(5 root(5 root(5 root(5... Since the expression inside the first root is equal to the entire expression, you get: x = root(5 x) Squaring both sides, to get rid of the rood, you get: x squared = 5x x squared - 5x = 0 x(x - 5) = 0 So, x is either equal to 0, or to 5. Indeed, if you start with any number and repeatedly multiply by 5 and then take the square root, you get closer and closer to 5... unless you start with zero, in which case you get exactly zero.
The square root needs to be removed from the bottom. To do this multiply the numberater and denominator by the square root of 5. 125xsquare root of five over 5 25square root of 5 is the simplest answer.
Square root 5: ± 2.236068Square root 9: ± 3